430=x^2+2.4+25

Solution for 430=x^2+2.4+25 equation:

430=x^2+2.4+25

We move all terms to the left:

430-(x^2+2.4+25)=0

We get rid of parentheses

-x^2-2.4-25+430=0

We add all the numbers together, and all the variables

-1x^2+402.6=0

a = -1; b = 0; c = +402.6;
Δ = b2-4ac
Δ = 02-4·(-1)·402.6
Δ = 1610.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1610.4}}{2*-1}=\frac{0-\sqrt{1610.4}}{-2}
=-\frac{\sqrt{}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1610.4}}{2*-1}=\frac{0+\sqrt{1610.4}}{-2}
=\frac{\sqrt{}}{-2}
$